Arithmetic Aptitude :: QE Quiz 10
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Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 10

Exercise

 "Life is like riding a bicycle. To keep your balance you must keep moving." - Albert Einstein
1 . Directions (Q. 1-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x > y
(2) if x $\geq$y
(3) if x < y
(4) if x $\leq$y
(5) if x = y or no relation between ‘x’ and ‘y’ can be established.

$Q.$
I. $3x^ 2$ – 7x – 20 = 0
II. $y^ 2$ – 8y + 16 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
2 . I. $x^ 2$ – 72 = 0
II. $y^ 2$ – 9y + 8 = 0
 $x > y$ $x \geq y$ $x < y$ x = y or no relation can be established between ‘x’ and ‘y’.
3 . I. $9x^ 2$ – 114x + 361 = 0
II. $y^ 2$ = 36
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
4 . I. 13x + 17y = 107
II. x – 11y = – 41
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
5 . I. $9x^ 2$ + 18x + 9 = 0
II. $y^ 2$ – 3y + 2 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
6 . I. 4x + 7y = 42
II. 3x - 11y = – l
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
7 . I. $9x^ 2$ – 29x + 22 = 0
II.$y^ 2$ – 7y + 12 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
8 . I. $3x^ 2$ – 4x – 32 = 0
II. $2y^ 2$ – 17y + 36 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
9 . I. $3x^ 2$ – 19x – 14 = 0
II. $2y^ 2$ + 5y + 3 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
10 . I. $x^ 2$ + 14x + 49 = 0
II. $y^ 2$ + 9y = 0
 $x > y$ $x \geq y$ $x < y$ x = y or no relation can be established between ‘x’ and ‘y’.