Free Online Test 360
Arithmetic Aptitude :: QE Quiz 19
Home » Arithmetic Aptitude » QE Quiz 19 » General Questions

free Online Test Quadratic Equation Questions and Answers Quiz 19

Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 19

Exercise

"Everyone is wise until he speaks."
- (Proverb)
1 . Directions (Q. 1 - 5) : In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x > y
(2) if x ≥ y
(3) if x < y
(4) if x ≤ y
(5) if x = y or no relation can be established between x and y.

$Q. $
I. $ x^ 2 $ - 2x - 15 = 0
II. $y^ 2$ + 5y + 6 = 0
A.  $ x > y$ B.    x ≥ y
C.  $ x < y$ D.    $ x ≤ y$
View Answer Workspace Report Discuss in Forum
2 . I. $ x^ 2 $ - x - 12 = 0
II. $y^ 2$ -3y + 2 = 0
A.  $ x > y$ B.    $ x \geq y $
C.  $ x < y$ D.    x = y or no relation can be established between ‘x’ and ‘y’.
View Answer Workspace Report Discuss in Forum
3 . I.$ x - \sqrt{169} = 0$
II.$ y^2 - \sqrt{169} = 0$
A.  $ x > y$ B.    x ≥ y
C.  $ x < y$ D.    $ x < y$
View Answer Workspace Report Discuss in Forum
4 . I. $x^2 - 32 = 112$
II. y - $\sqrt{256}$ = 0
A.  $ x > y$ B.    $ x \geq y $
C.  $ x < y$ D.    $ x \leq y$
View Answer Workspace Report Discuss in Forum
5 . I. $ x^ 2$ - 25 = 0
II. $y^ 2$ - 9y + 20 = 0
A.  $ x > y$ B.    $ x \geq y $
C.  $ x < y$ D.    x = y or no relation can be established between ‘x’ and ‘y’.
View Answer Workspace Report Discuss in Forum
6 . Directions (Q. 6 - 10): In the following questions, three equations numbered I, II and III are given. You have to solve all the equations either together or separately, or two together and one separately or by any other method and give answer
(1) if x = y > z
(2) if x < y = z
(3) if x < y > z
(4) if x = y = z or if none of the above relationship can be established.
(5) if x ≤ y < z

$Q.$
I. 3x + 5y = 69
II. 9x + 4y = 108
III. x + z = 12
A.  x = y > z B.    x < y = z
C.  x < y > z D.    x = y = z or if none of the above relationship can be established.
View Answer Workspace Report Discuss in Forum
7 . I . $y = \sqrt{9^{3 \times {1\over3}} \times {9^{3 \times {1\over3}}}} $ = $\sqrt{9 \times 9}$ = 9
II. 2x + 5z = 54
III. 6x + 4z = 74
A.  x = y > z B.    x < y = z
C.  x < y > z D.    x ≤ y < z
View Answer Workspace Report Discuss in Forum
8 . I. 2x + 3y + 4z = 66
II. 2x + y + 3z = 42
III. 3x + 2y + 4z = 63
A.  x = y > z B.    x < y = z
C.  x < y > z D.    x ≤ y < z
View Answer Workspace Report Discuss in Forum
9 . I. $(x + z)^ 3$ = 1728 = $ 12^ 3$
II. 2x + 3y = 35
III. x - z = 2
A.  x = y > z B.    x < y = z
C.  x < y > z D.    x ≤ y < z
View Answer Workspace Report Discuss in Forum
10 . I. 4x + 5y = 37
II. x + z = 8
III. 7x + 3y = 36
A.  x = y > z B.    x < y = z
C.  x < y > z D.    x ≤ y < z
View Answer Workspace Report Discuss in Forum

© 2016 by onlinetest360.com . All Rights Reserved | Copyright | Terms of Use & Privacy Policy

Contact us: info@onlinetest360.com     A venture of Jenisys Systems Pvt Ltd

DMCA.com Protection Status