Arithmetic Aptitude :: QE Quiz 20
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Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 20

Exercise

 "The secret to creativity is knowing how to hide your sources." - Albert Einstein
1 . Directions (Q. 1 - 5): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x < y
(2) if x ≤ y
(3) if x = y or no relation can be established
(4) if x > y
(5) if x ≥ y

$Q.$
I. 7x + 3y = 77
II. 2x + 5y = $(2601)^{1\over 2}$ = 51
 x < y x ≤ y x = y or no relation can be established x > y
2 . I. $3x^2 - 6x - \sqrt{17}x + 2\sqrt{17}$ = 0
II. $10y^2 - 18y - 5\sqrt{17}y + 9\sqrt{17}$ = 0
 x < y x ≤ y x = y or no relation can be established x > y
3 . I . $(289)^{1\over 2} x$ - $\sqrt{324}$ = 203
II. $(484)^{1\over 2} y$ - $\sqrt{225}$ = 183
 x < y x ≤ y x = y or no relation can be established x > y
4 . I . $511 x^2$ = 3066
II. $12y^ 3$ - $9y^ 3$ = 1536
 x < y x ≤ y x > y x ≥ y
5 . Directions (Q. 5 - 7): In the following questions two equations numbered I and II are given. Solve both the equations and give answer
(1) if x < y
(2) if x ≥ y
(3) if x ≤ y
(4) if x > y
(5) if x = y or no relationship can be established

$Q.$
I. 3x + 4y = (4681)$^{1\over 2}$
II. 3x + 2y = $(961)^{1\over 2}$
 x < y x ≥ y x ≤ y x > y
6 . I. $3x^2 - 6x - \sqrt{17}x + 2\sqrt{17}$ = 0
II. $10y^2 - 15y + \sqrt{17}y - 3\sqrt{17}$ = 0
7 . I. $x^ 2$ - 16x + 63 = 0
II. $y^ 2$ - 2y - 35 = 0