Arithmetic Aptitude :: QE Quiz 5
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Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 5

Exercise

 "When ambition ends, happiness begins." - (Proverb)
1 . Directions (Q. 1-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x > y
(2) if x $\geq$y
(3) if x < y
(4) if x $\leq$y
(5) if x = y or relationship between x and y cannot be established
$Q.$
I. $7x^ 2$ - 9x + 2 = 0
II. $y^ 2$ - 4y + 3 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
2 . I.$x^ 2$ = 64
II. $2y^ 2$ + 25y + 72 = 0
 $x > y$ $x \geq y$ $x \leq y$ x = y or no relation can be established between ‘x’ and ‘y’.
3 . I. $x^ 2$ + x - 20 = 0
II. $2y^ 2$ - 19y + 45 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
4 . I. 7x + 3y = 26
II. 2x + 17y = -41
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
5 . I. $3x^ 2$ - 20x + 33 = 0
II. $2y^ 2$ - 11y + 15 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
6 . I. $4x^ 2$ - 43x + 105 = 0
II. $7y^ 2$ - 29y + 30 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
7 . I. $x^ 2$ + 13x + 40 = 0
II. $y^ 2$ + 7y + 10 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
8 . I . x = $\sqrt[3]{2197}$
II. $2y^ 2$ - 54y + 364 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
9 . I.$5x^ 2$ - 27x + 36 = 0
II. $y^ 2$ - 2y + 2 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
 $x > y$ $x \geq y$ $x < y$ $x \leq y$