Arithmetic Aptitude :: QE Quiz 6
Home » Arithmetic Aptitude » QE Quiz 6 » General Questions

Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 6

Exercise

 "I never see what has been done; I only see what remains to be done." - Marie Curie
1 . Directions (Q. 1-5): Two equations (I) and (II) are given in each question. On the basis of these equations, you have to decide the relation between x and y and give answer
(1) if x > y
(2) if x < y
(3) if x $\geq$y
(4) if x $\leq$y
(5) if x = y, or no relation can be established between x and y.

$Q.$
I. $15x^ 2$ - 19x + 6 = 0
II. $6y^ 2$ - 5y + 1 = 0
 $x > y$ $x < y$ $x \geq y$ $x \leq y$
2 . I. x = $\sqrt{172}$
II. $y^ 2$ - 29y + 210 = 0
 $x > y$ $x < y$ $x \geq y$ $x \leq y$
3 . I. $3x^ 2$ - 20x + 32 = 0
II. $2y^ 2$ - 19y + 44 = 0
 $x > y$ $x < y$ $x \geq y$ $x \leq y$
4 . I. 3x + 8y = -2
II. 4x + 18y = 1
 $x > y$ $x < y$ $x \geq y$ $x \leq y$
5 . I. $2x^ 2$ - 15x + 28 = 0
II.$10y^ 2$ - y - 119 = 0
 $x > y$ $x < y$ $x \geq y$ $x \leq y$
6 . Directions (Q. 6-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x > y
(2) if x $\geq$ y
(3) if x < y
(4) if x $\leq$ y
(5) if x = y or relationship between x and y cannot be established.

$Q.$
I. 676$x^2$ - 1 = 0
II. y = $1\over \sqrt[3]{13824}$
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
7 . I. 8x + 13y = 62
II 13x - 17y + 128 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
8 . I. $x^ 2$ = 7x
II. $(y + 7)^ 2$ = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
9 . I.$7x^ 2$ + 2x = 120
II. $y^ 2$ + 11y + 30 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
10 . I.$2x^ 2$ + 5x - 33 = 0
II. $y^ 2$ - y - 6 = 0
 $x \geq y$ $x < y$ $x \leq y$ x = y or no relation can be established between ‘x’ and ‘y’.