Arithmetic Aptitude :: QE Quiz 8
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Description: Free Online Test questions and answers on Quadratic Equation with explanation for various competitive exams,entrance test. Solved examples with detailed answer test 8

Exercise

 "Hold a true friend with both hands." - (Proverb)
1 . Directions (Q. 1-5): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if x > y
(2) if x $\geq$y
(3) if x < y
(4) if x $\leq$y
(5) if x = y or a relationship between x and y cannot be established.

$Q.$
I. $x^ 2$ + 3x = 28
II. $y^ 2$ + 16y + 63 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
2 . I. x = $\sqrt[3]{2197}$
II. y$^2$ = 169
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
3 . I. $8x^ 2$ - 49x + 45 = 0
II.$8y^ 2$ - y - 9 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
4 . I. 42x - 17y = -67
II. 7x + 12y = -26
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
5 . I. $x^ 2$ - 8x + 15 = 0
II. $2y^ 2$ - 21y + 55 = 0
 $x > y$ $x \geq y$ $x < y$ $x \leq y$
6 . Directions (Q. 6-10): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
(1) if p > q
(2) if p $\geq$ q
(3) if p < q
(4) if p $\leq$ q
(5) if p = q or no relation can be established between p and q.

$Q.$
I. $2.3p - 20.01 = 0$
II. $2.9q - p = 0$
 $p > q$ $p \geq q$ $p < q$ $p \leq q$
7 . I. p = $\sqrt{1764}$
II. $q^2$ = 1764
 $p > q$ $p \geq q$ $p < q$ $p \leq q$
8 . I. $p^ 2$ - 26p + 168 = 0
II. $q^ 2$ - 25q + 156 = 0
 p = q or no relation can be established between ‘p’ and ‘q’. $p \leq q$ $p < q$ $p \geq q$
9 . I. $p^ 2$ - 13p + 42 = 0
II. $q^ 2$ + q - 42 = 0
 $p > q$ $p \geq q$ $p < q$ $p \leq q$
 $p > q$ $p \geq q$ $p < q$ $p \leq q$